Hi All,
So I have a joystick hooked up and working....when I press a button, it sends a bang...and when I release the button, it sends another one.

How can I route these events to seperate objects?

For every press, there is a release...so they are ALWAYS in pairs..I was thinking of using the first bang to set a counter, and the second one to unset it...but that doesn't really work.

There is another number object that is 1 when a button is pressed, and 0 when not pressed...I think this would be useful, but not sure how.

Any thoughts?

Thanks,
AltReality

If you use a toggle it will do what you want.

Then if you run it into [select 0 1] you can sort those.

i assume you mean that the right outlet of the joystick object ouputs a 1 or zero and the left outlet outputs a bang?

in that case:

[joystick] (or whatever it is you are using)
| |
[spigot]
|
[your bang is output here only on input]

hi all,

I made a little software flip-flop for myself for precisely this type of scenario.

It's probably computationally expensive but it does precisely what I needed (route signal to alternating outlets) + it was a fun challenge

http://www.pdpatchrepo.info/hurleur/flip_flop.pd

This is the simplest flip-flop i could come up with.

http://www.pdpatchrepo.info/hurleur/easyFlipFlop.pd

nice domien!

and with your version it's just a couple of steps to do a three, four, however many outlets to bang sequentially.

d

Thanks for the quick responses all!...
So Domien, yours works perfectly...but I wonder if you could explain the center part to me..I'm having trouble wrapping my brain around it.

[F 0]X[==0]
|
[sel 0 1] (It works, but I don't understand why)

Secondly...
How can I adapt this to this scenerio..
[0\ (This is hooked to a button...it sets a number, and bangs twice..once for pressed, once for released)
|
[route 1 2 3 4 5] (actually there are 12 potential routes)

Each route needs a [pd easyflipflop] but the second bang on each one I want to do the exact same thing....
It seems wrong to put 12 subpatches in here...

Does that make sense?

Do any of you ever visit the IRC channel? I think live chat might be an easier way to explain it.

Here's my patch if you are interested...it should work with any joystick in Windows.
Thanks

http://www.pdpatchrepo.info/hurleur/joystickmapmidicontrol.pd

A bang on the left input of [f] causes it to output whatever number is stored. This must be either zero or non-zero at any time. If it is zero then [== 0] is true and produces a 1, otherwise it is false and a 0 is returned. The outlet (1 or 0) from [== 0] goes to the right inlet of [f] so this becomes the next number.

Now;
if the last value was 0 then [== 0] must return 1 so the next number will be 1
if the last value was 1 then [== 0] must return 0 so the next value wil be zero.

Therefore the flip-flop always has the opposite of its last state when banged.

Don't worry about using 12 flip-flops, that's okay.

aahh..I was forgetting the [== 0] outputting a 1..that's what I couldn't get.
Thanks for the explanation...
So any thoughts on the second part though? I really really think there's a more elegant way to do it....I'm just not well-versed enough in the program to figure it out

Thanks,
AltReality