Hello

Having a bit of trouble getting my head around structuring ramps using vline~ and wondered if someone would mind explaining it a bit.

I've looked at the vline~ help file but I'm evidently missing something....

The example they give is:

[1 1000, 0 0 1000, 1 1000 1000]

ramp up, jump down, ramp up again.

I understand the logic of the first ramp up as being "take 1000ms to reach 1" but beyond that I get a bit lost. Why two lots of zeros for the ramp down and then a 1 1000 to ramp back up?

What I want to do is to ramp up to 1 and then ramp back down again softly, kind of like having a [1 1000] message followed by [0 1000] but combined.

Thanks

pmj

well, vline~ takes 3 values every time:

1. value where the ramp should end up
2. time, that it takes to get there
3. delaytime, before the ramp starts

in the example you posted you could also type instead:

[1 1000 0, 0 0 1000, 1 1000 1000]

what means:
1. count from the inital value until 1 in 1000 ms with no delay
2. count from 1 to 0 in 0 ms (jump) after a delaytime of 1000 ms (this is needed, because the first message needs 1000 ms to process)
3. count from 0 to 1 again in 1000 ms but start this operation after a delaytime of 1000 ms (bacause the previous two operations need 1000 ms to be processed (first needs 1000 ms, second needs 0 ms (jump)).

god, i hope you understood this, it's quite easy but my english is a bit poor!

for the thing you want to you could do it like this:

[0 0 0, 1 1000 0, 0 1000 1000]

means:

1. set initial value 0 (in 0 ms, with no delay)
2. count from 0 to 1 in 1000 ms, imediatly
3. count back to 1 in 1000 ms after a delaytime of 1000 ms (...after the second operation, which needs 1000 ms to process)

Thanks, that explains it... cheers for you help.

.... [0, 1 1000, 0 1000 1000] does the same as your example for my requested ramp too? It seems to.

yes, it should. i only posted the whole tag to make clear what it's all about.