Hi.
I have an argument for an abstraction that looks like

[myabstraction foo/bar/baz]

Inside of my abstraction I'm calculating a float and I want to send a message like

[foo bar baz 0.23(

So that I can later do

[route foo]

and get "bar baz 0.23"

So far, I'm doing:

[symbol $1]
|
|
[s2l /]
|
|
[0.22( [l2s]
| |
| |
[pack f s]
|
|
[$2 $1(
| \
| \
[print] [route foo]
|
|
[print no_output]

Which successfully prints "foo bar baz 0.22" on the left print object. However, there is nothing printed by [print no_output].

Any ideas why? I'm thinking the conversion from symbol to list and back does something weird that is not seen by [print] ?

Any other suggestion on how to achieve this?

Thanks!

I believe what is happening in your example is that the packed list is just "one" signal, which is why the whole thing goes out one outlet (not just part of it). Nothing goes out the right outlet, there was only one signal, there's no 2nd signal to go there.

For list management, I suggest reading up on the list objects such as

and .

I'd also read up on the message box manipulation messages, open HELP for a message box and click on the box that says:
pd messages_for_changing_the_contents_of_a_message_box

Thanks a lot shawnb! The messages_for_changing_the_contents_of_a_message_box part is what I was missing
I ended up using [add( messages to a message box in conjunction with [dollarg] to achieve what I described.